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Middle school🔢Arithmetic●○○○○· 3 min
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Divisibility by 3 and 9: add up the digits

A number is divisible by 3 (or 9) if the sum of its digits is. Mind-blowing test, works for all integers.

The two rules

  • Divisible by 3: the sum of digits is divisible by 3.
  • Divisible by 9: the sum of digits is divisible by 9.

In one picture

Take 471471:

  • Sum of digits: 4+7+1=124 + 7 + 1 = 12.
  • 1212 is divisible by 3 → 471 is divisible by 3 ✓ (check: 471=3×157471 = 3 \times 157).
  • 1212 isn’t divisible by 9 → 471 isn’t divisible by 9.

Take 342342:

  • 3+4+2=93 + 4 + 2 = 9 → divisible by 3 and 9 ✓ (check: 342=9×38342 = 9 \times 38).

The shortcut of the shortcut

If the sum is still big, sum again. Example 918273918273:

  • 9+1+8+2+7+3=309 + 1 + 8 + 2 + 7 + 3 = 30
  • 3+0=33 + 0 = 3 → divisible by 3, not by 9.

Why it works

Every power of 10 equals 11 modulo 9 (because 10=9+110 = 9 + 1). So a number is congruent to the sum of its digits modulo 9. Divisible by 9 = digit sum divisible by 9. Same for 3 since 9=3×39 = 3 \times 3.

?Your turn

Is 2718 divisible by 9?

?Your turn

Among these 4 numbers, which one is NOT divisible by 3?

#divisibility#arithmetic#rules#3#9

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