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High school∫Calculus12 min read
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Antiderivatives: Complete Lesson with Formulas and Methods

The inverse of differentiation. Key formulas, linearity, pattern recognition. Grade 12 lesson.

Prerequisites :

  • Derivatives
  • Exponential function
  • Logarithm

Definition

A function FF is an antiderivative of ff on an interval II if:

Fβ€²(x)=f(x)Β forΒ allΒ x∈IF'(x) = f(x) \text{ for all } x \in I

Antidifferentiation is the inverse of differentiation.

Fundamental property

Two antiderivatives of the same function differ by a constant.

If FF and GG are antiderivatives of ff, then G(x)=F(x)+CG(x) = F(x) + C for some C∈RC \in \mathbb{R}.

So we typically write β€œthe” antiderivative as:

F(x)+CF(x) + C

Standard formulas

f(x)f(x)Antiderivative F(x)F(x)Domain
kk (constant)kxkxR\mathbb{R}
xnx^n (nβ‰ βˆ’1n \neq -1)xn+1n+1\dfrac{x^{n+1}}{n+1}R\mathbb{R} (or Rβˆ—\mathbb{R}^* if n<0n < 0)
1x\dfrac{1}{x}ln⁑βˆ₯xβˆ₯\ln\|x\|xβ‰ 0x \neq 0
1x\dfrac{1}{\sqrt{x}}2x2\sqrt{x}x>0x > 0
exe^xexe^xR\mathbb{R}
sin⁑(x)\sin(x)βˆ’cos⁑(x)-\cos(x)R\mathbb{R}
cos⁑(x)\cos(x)sin⁑(x)\sin(x)R\mathbb{R}
11+x2\dfrac{1}{1+x^2}arctan⁑(x)\arctan(x)R\mathbb{R}

Linearity

∫(af+bg)=a∫f+b∫g\int (af + bg) = a \int f + b \int g

Antiderivative of a sum = sum of antiderivatives.

Example: antiderivative of 3x2βˆ’5x+73x^2 - 5x + 7? F(x)=x3βˆ’5x22+7x+CF(x) = x^3 - \dfrac{5x^2}{2} + 7x + C.

Chain pattern: uβ€²β‹…vβ€²(u)u' \cdot v'(u)

If you spot uβ€²(x)β‹…vβ€²(u(x))u'(x) \cdot v'(u(x)), an antiderivative is v(u(x))v(u(x)).

Common cases:

  • ∫uβ€²β‹…un=un+1n+1\displaystyle \int u' \cdot u^n = \dfrac{u^{n+1}}{n+1} (nβ‰ βˆ’1n \neq -1)
  • ∫uβ€²u=ln⁑∣u∣\displaystyle \int \dfrac{u'}{u} = \ln|u|
  • ∫uβ€²β‹…eu=eu\displaystyle \int u' \cdot e^u = e^u
  • ∫uβ€²β‹…cos⁑(u)=sin⁑(u)\displaystyle \int u' \cdot \cos(u) = \sin(u)

Example 1: antiderivative of 2xβ‹…ex22x \cdot e^{x^2}. u=x2u = x^2, uβ€²=2xu' = 2x. Antiderivative: ex2e^{x^2}.

Example 2: antiderivative of 2xx2+1\dfrac{2x}{x^2 + 1}. u=x2+1u = x^2 + 1. Antiderivative: ln⁑(x2+1)\ln(x^2 + 1).

Initial condition

Often we want THE antiderivative with a specific value, e.g. F(0)=3F(0) = 3.

Example: find FF antiderivative of f(x)=2xf(x) = 2x with F(0)=5F(0) = 5. F(x)=x2+CF(x) = x^2 + C. F(0)=C=5F(0) = C = 5. So F(x)=x2+5F(x) = x^2 + 5.

Connection to definite integral

∫abf(x) dx=F(b)βˆ’F(a)\int_a^b f(x)\, dx = F(b) - F(a)

Fundamental theorem of calculus.

Common mistakes

  1. Forgetting +C+ C.
  2. Confusing antiderivative and derivative.
  3. Not verifying: differentiate to check.
  4. Dividing by n+1=0n + 1 = 0: for n=βˆ’1n = -1 (1x\dfrac{1}{x}), antiderivative is ln⁑∣x∣\ln|x|, not x00\dfrac{x^0}{0}.

Solved exercises

Exercise 1

Antiderivative of f(x)=4x3βˆ’6x+2f(x) = 4x^3 - 6x + 2.

Show solution

F(x)=x4βˆ’3x2+2x+CF(x) = x^4 - 3x^2 + 2x + C.

Exercise 2

Antiderivative of 3x2x3+1\dfrac{3x^2}{x^3 + 1}.

Show solution

u=x3+1u = x^3 + 1, uβ€²=3x2u' = 3x^2. F(x)=ln⁑∣x3+1∣+CF(x) = \ln|x^3 + 1| + C.

Exercise 3

Antiderivative of cos⁑(2x)\cos(2x).

Show solution

u=2xu = 2x, uβ€²=2u' = 2. F(x)=12sin⁑(2x)+CF(x) = \dfrac{1}{2}\sin(2x) + C.

Takeaways

  • Fβ€²=fF' = f defines FF.
  • Antiderivatives differ by a constant.
  • Always add +C+ C.
  • Spot chain patterns uβ€²vβ€²(u)u' v'(u).
  • Verify by differentiating.
#antiderivatives#integration#grade 12#AP calc