The big picture
The exponential function, written exp or xβ¦ex, is the most important function in calculus. It has a unique property: it equals its own derivative.
Definition
exp:RβR+ββ
The unique function on R such that:
- exp(0)=1
- For all real x, expβ²(x)=exp(x) (derivative equals the function itself)
Also written exp(x)=ex, where eβ2.71828β¦
The 5 essential algebraic properties
These look like power rules β they come up all the time:
| Property | Formula |
|---|
| Sum in exponent | ea+b=eaΓeb |
| Difference | eaβb=ebeaβ |
| Opposite | eβa=ea1β |
| Power | (ea)n=ena |
| Root | ea/2=eaβ |
Derivative
Fundamental:
(ex)β²=ex
General (chain rule):
(eu(x))β²=uβ²(x)β
eu(x)
Move the slider below: at every x, the tangent slope equals the functionβs value.
Examples:
- (e3x)β²=3e3x
- (eβx)β²=βeβx
- (ex2)β²=2xβ
ex2
Monotonicity
For all xβR, ex>0 (exponential is always strictly positive).
So (ex)β²=ex>0 β exp is strictly increasing on R.
Consequence: exp is bijective from R to R+ββ. Its inverse is the natural log ln.
Limits to memorize
| Limit | Value |
|---|
| limxβ+ββex | +β |
| limxββββex | 0 |
| limxβ+ββxexβ | +β (comparative growth) |
| limxβ+ββxnexβ | +β for all n |
| limxββββxβ
ex | 0 |
| limxβ0βxexβ1β | 1 (derivative at 0) |
Comparative growth: exponential beats any power at +β.
Equations and inequalities
Since exp is strictly increasing:
- ea=ebβΊa=b
- ea<ebβΊa<b
Example 1: equation
Solve e2xβ3=ex+1.
By bijection: 2xβ3=x+1, so x=4.
Example 2: with a constant
Solve ex=5.
Using ln: x=ln(5)β1.61.
Example 3: inequality
Solve e2xβ1β₯e3x+2.
By strict growth: 2xβ1β₯3x+2βΊxβ€β3.
Full study: f(x)=xeβx
A classic exam question.
Domain: R.
Derivative: fβ²(x)=eβx(1βx).
Sign of fβ²: since eβx>0, sign of (1βx):
- fβ²>0 for x<1
- fβ²<0 for x>1
Extremum: max at x=1, f(1)=1/eβ0.37.
Limits:
- As xβββ: eβxβ+β and xβββ, so f(x)βββ.
- As xβ+β: x/exβ0.
Real-world applications
- Population growth: N(t)=N0ββ
ekt
- Radioactive decay: N(t)=N0ββ
eβΞ»t
- Capacitor charging: u(t)=U(1βeβt/Ο)
- Continuous compound interest: C(t)=C0ββ
ert
Common mistakes
- Confusing ea+b with ea+eb: itβs a product (eaΓeb), not a sum.
- Forgetting uβ² in chain rule: (e2x)β²=2e2x, NOT e2x.
- Thinking eβx can be negative: NO, exponential is always > 0.
- ln and e are inverses: ln(ex)=x and eln(x)=x (for x>0).
Solved exercises
Exercise 1
Simplify e2xβ
eβ3x.
Show solution
Sum exponents: eβx.
Exercise 2
Solve ex2=e2x+3.
Show solution
By bijection: x2=2x+3, so x2β2xβ3=0.
Ξ=16, roots β1 and 3.
Exercise 3
Study monotonicity of g(x)=ex2β2x.
Show solution
gβ²(x)=(2xβ2)ex2β2x. Since e...>0:
- gβ²<0 for x<1
- gβ²>0 for x>1
g decreases on (ββ,1], increases on [1,+β). Min at x=1: g(1)=1/e.
Takeaways
- exp(0)=1, expβ²=exp.
- Always strictly positive, strictly increasing, bijective.
- ea+b=eaeb, eβa=1/ea.
- Chain rule: (eu)β²=uβ²eu.
- Beats any power at +β.
- Inverse: ln.
Going further