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High school🧩Logic●○○○○· 3 min
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Sets: intersection ∩ and union ∪ in 2 minutes

∩ = and. ∪ = or. Two symbols, two operations, one logic. Math's vocabulary.

Intersection: A∩BA \cap B

A∩B={x ∣ x∈A AND x∈B}A \cap B = \{x \, | \, x \in A \text{ AND } x \in B\}

Elements in AA AND in BB at the same time.

Example: A={1,2,3,4}A = \{1, 2, 3, 4\}, B={3,4,5,6}B = \{3, 4, 5, 6\} ⇒ A∩B={3,4}A \cap B = \{3, 4\}.

Union: A∪BA \cup B

A∪B={x ∣ x∈A OR x∈B}A \cup B = \{x \, | \, x \in A \text{ OR } x \in B\}

Elements in AA OR in BB (or both).

Example: A∪B={1,2,3,4,5,6}A \cup B = \{1, 2, 3, 4, 5, 6\}.

On intervals

[1,5]∩[3,7]=[3,5][1, 5] \cap [3, 7] = [3, 5]

[1,5]∪[3,7]=[1,7][1, 5] \cup [3, 7] = [1, 7]

Special cases

  • A∩A=AA \cap A = A, A∪A=AA \cup A = A.
  • A∩∅=∅A \cap \emptyset = \emptyset, A∪∅=AA \cup \emptyset = A.
  • If A⊂BA \subset B: A∩B=AA \cap B = A, A∪B=BA \cup B = B.

Complement

A‾={x ∣ x∉A}\overline{A} = \{x \, | \, x \notin A\}

In a reference set EE, A‾=E∖A\overline{A} = E \setminus A.

De Morgan’s laws

A∩B‾=A‾∪B‾\overline{A \cap B} = \overline{A} \cup \overline{B}

A∪B‾=A‾∩B‾\overline{A \cup B} = \overline{A} \cap \overline{B}

“Negation swaps AND and OR”.

Venn diagram

Two overlapping circles:

  • Intersection = common zone (middle).
  • Union = whole picture.

Common mistakes

  1. Confusing ∩\cap (and) with ∪\cup (or).
  2. Writing A∩B=A∪BA \cap B = A \cup B carelessly.
  3. Using ∈\in (element) and ⊂\subset (subset) interchangeably.
?À toi de jouer

A = [0, 4] and B = [2, 6]. A ∩ B = ?

Mini-quiz

Question 1 / 3

A = {1, 2, 3, 5}, B = {2, 3, 4}. A ∩ B?

#sets#intersection#union#logic#grade 10

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