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Quadratic equation: the discriminant in 5 seconds

$\Delta = b^2 - 4ac$. Three cases, three scenarios. The universal method for all $ax^2 + bx + c = 0$.

The universal method

To solve ax2+bx+c=0ax^2 + bx + c = 0 (with aโ‰ 0a \ne 0), compute the discriminant:

ฮ”=b2โˆ’4ac\Delta = b^2 - 4ac

Then look at the sign of ฮ”\Delta:

CaseNumber of solutionsFormula
ฮ”>0\Delta > 0Two distinct solutionsx1,2=โˆ’bยฑฮ”2ax_{1,2} = \dfrac{-b \pm \sqrt{\Delta}}{2a}
ฮ”=0\Delta = 0One double solutionx0=โˆ’b2ax_0 = \dfrac{-b}{2a}
ฮ”<0\Delta < 0No real solutionโ€”

Example: x2โˆ’5x+6=0x^2 - 5x + 6 = 0

  • a=1a = 1, b=โˆ’5b = -5, c=6c = 6.
  • ฮ”=(โˆ’5)2โˆ’4โ‹…1โ‹…6=25โˆ’24=1\Delta = (-5)^2 - 4 \cdot 1 \cdot 6 = 25 - 24 = 1.
  • ฮ”>0\Delta > 0 โ†’ two solutions.
  • x1=5+12=3x_1 = \dfrac{5 + 1}{2} = 3, x2=5โˆ’12=2x_2 = \dfrac{5 - 1}{2} = 2.

The key move

Always write down aa, bb, cc before computing ฮ”\Delta. This is where 90% of sign mistakes happen.

Verification trick

Sum of roots = โˆ’b/a-b/a, product of roots = c/ac/a. A quick check on your work.

On the example: x1+x2=5x_1 + x_2 = 5 and โˆ’b/a=5-b/a = 5 โœ“. x1ร—x2=6x_1 \times x_2 = 6 and c/a=6c/a = 6 โœ“.

?Your turn

How many solutions does 2xยฒ โˆ’ 4x + 5 = 0 have?

Mini-quiz

Question 1 / 3

How many real solutions does xยฒ โˆ’ 4x + 3 = 0 have?

#quadratic#discriminant#equation#roots

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